Data Interpretation Solved questions: Bar graph

Bar graph Data interpretation solved practice questions.

Question.1.The bar graph given below shows the foreign exchange reserves of a country (in million US $) from 1991-92 to 1998-99. Answer the questions based on this graph.

1.The foreign exchange reserves in 1997-93 was how many times that in 1994-95 ?

(a) 0.7

(b) 1.2

(c) 1.4

(d) 1.5

(e) 1.8 1

2.What was the percentage increase in the foreign exchange reserves in 1997-98 over 1993-94 ?

(a)100

(b)150

(c)200

(d)620

(e)2520

3.For which year, the percent increase of foreign exchange reserves over the previous year, is the highest?

(a)1992-93

(b)1993-94

(c)1994-95

(d)1996-97

(e)1997-98

4. The foreign exchange reserves in 1996-97 were approximately what percent of the average foreign exchange reserves over the period under review ? ,

(a) 95%

(b) 110%

(c) 115%

(d) 125%

(e) 140%

5, The ratio of the number of years, in which the foreign exchange reserves are above the average reserves, to those in which the reserves are below the average reserves, is :

(a)2:6

(b)3:4

(c)3:5

(d)4;4

(e)5:3

Solutions:

Sol. 1.(d) : Required ratio = 5040/3360=1.5

Sol.2. (a). Foreign exchange reseryes in 1997-98 = 5040 million US $

Foreign exchange reserves in 1993-94 = 2520 million US $

Increase = (5040 — 2520) = 2520 million US $.

Percentage increase =[ (2520/2520) x 100)]% = 100%.

Sol.3. (a) : There is an increase in foreign exchange reserves during the years 1992-93, 1994-95 1996-97 and 1997-98 as compared to previous year (as shown by bar-graph). The percentage increase in reserves during these years compared to previous year are :

(i) For 1992-93 =[{(3720-2640)/2640 }* 100] % = 40.91%

(ii) F01‘ 1994-95 =[{(3360 - 2520)/2520}* 100] % = 33.33%

(iii) For 1996-97 =[{(4320 - 3120)/3120}*100] % = 38.46%

(iv) For 1997-98 =[{ (5040 - 4320)/4320}*100] % = 16.67%

Clearly, the percentage increase over previous year is highest for 1992-93.

Sol.4. (d) : Average foreign exchange reserves over the given period

= [(2640 + 3720 + 2520 + 3360 + 3120+ 4320 + 5040 + 3120)] million US $

= 3480 million US $.

Foreign exchange reserves in 1996-97 = 4320 million US $.

Required Percentage = [( 4320/3480)*100)]% = 124.14% = 125%.

Sol.5. (c)Average foreign exchange reserves over the given period = 3480 million US$.

The country had reserves above 3480 million US $ during the years 1992-93, 1996-97 and

1997-98 ie., for 3 years and below 3480 million US$ during the years 1991-92, 1993-94,

1994-95, 1995-96 and 1998-99 ie., for5 years.

Hence, required ratio = 3 :5

Question.2.The Bar graph provided below gives the sales of books from six branches of a publishing company during two consecutive years 2000 and 2001.Answer the questions based on this graph.

1. Total sales of branches B1, B3 and B5 together for both the years (in thousand numbers)is

(a) 250

(b) 310

(c) 435

(d) 560

(e) 585

2.Total sales of branch B6 for both the years is what percent of the total sales of branch

B3 for both-the years ?

(a) 68.54%

(b) 71.11%

(c) 73.17%

(d) 75.55%

(e) 77.26%

3.What is the average sale of all the branches (in thousand numbers) for the year 2000 ?

(a)73

(b) 80

(c) 83

(d) 88

(e) 95

4.What is the ratio of the total sales of’ branch B2 for -both years to the total sales of

branch B4 for both years ?

(a)2:3

(b)3:5

(c)425

(d)5:7

(e)7:9

5.What percent of the average sales of branches B1, B2 and B3 in 2001 is the average sales

of branches B1, B3 and B6 in 2000 ?

(a) 75%

(b) 77.5%

(c) 82.5%

(d) 85%

(e) 87.5%

Solutions:

Sol. 1. (d) : Total sales of branches B1, B3 and B5 for both the years (in thousand numbers)

= (80 + 105) + (95 + 110) + (75+ 95) = 560.

Sol. 2. (c) : Required Percentage = [{(70+80)/(95+110)} *100]% = 73.17%.

Sol.3. (b) : Average sales of all the ,six branches (in thousand numbers) for the year 2000 =

(1/6)*[80+ 75 +95 + 85+ 75 + 70] = 80.

Sol.4.(e) : Required [(75+65)/(85+95)]=7/9

Sol.5.(e): Average sales (in thousand numbers) of branches B1, B3 and B6 in 2000

=(1/3)*(80+95+70)=245/3

Average sales (in thousand numbers) of branches B1, B2 and B3 in 2001

(1/3)*(105+65+110) =280/3

Required Percentage =[(245/3)/(280/3)]*100% = 87.5%

Question.3. The bar graph given below shows the percentage distribution of the total production of a car manufacturing company into various models over two years. Study the graph carefully and answer the questions that follow.(Total no of cars produced in 2000=3,50,000 and Total cars produced in 2001=4,40,000 )

1. Total number of cars of models P, Q and T manufactured in 2000 is

(a) 2,45,000

(b) 2,27,500

(c) 2,10,000

(d) 1,92,500

(e)1,57,500

2. For which model the percentage rise/ fall in production from 2000 to 2001 was minimum?

(a)Q

(b)R

(c)S

(d)T

(e)U

3. What was the difference in the number of Q type cars produced in 2000 and that produced in 2001?

(a) 35,500

(b) 27,000

(c) 22,500

(d)17,5000

(e) 16,000

4. If the percentage production of P type cars in 2001 was the same as that in 2000, then the number of P type cars produced in 2001 would have been:

(a) 1,40,000

(b) 1,32,000

(c) 1,17,000

(d) 1,05,000

(e) 97,000

5. If 85% of the S type cars produced in each year were sold by the Company, how many S type cars remained unsold ?

(a) 7650

(b) 9350

(c)11,850

(d) 12,250

(e) 13,350

 Solutions:

Sol. 1.(c) We shall first, determine the number of cars of each model produced by the Company during the two years

In 2000 Total number of cars produced = 3,50,000.

P= (30 - 0)% of 3,50,000 = 30% of 3,50,000 =1,05,000

Q=(45-30)% of 3,50,000 15% of 3,50,000 =52,500

R (65 - 45)% of 3,50,000 = 20% of 3,50,000 = 70,000

S=(75 - 65)% of 3,50,000 10% of 3,50,000 =35,000

T =(90 - 75)% of 3,50,000 15% of 3,50,000 =52,500

U=(100 -90)% of 3,50,000 10% of 3,50,000=35,000.

In 2001 Total number of cars produced = 4,40,000.

P= (40 - 0)% of 4,40,000 = 40% of 4,40,000 = 1,76,000

Q=(60- 40)% of 4,40,000 20% of 4,40,000= 88,000

R=(75- 60)% of 4,40,000 = 15% of 4,40,000 =66,000

S= (85 - 75)% of 4,40,000 = 10% of 4,40,000 = 44,000

T=(95 - 85)% of 4,40,000 = 10% of 4,40,000 =44,000

U=(100 95)% of 4,40,000 5% of 4,40,000 = 22,000

Now, we shall solve the questions.

Total number of cars of models P, Q and T manufactured in 2000

= (105000+ 52500 +52500) = 2,10,000.

 Sol.2.(b). Using the above calculation, the percentage change (rise/ fall) in production from 2000 to 2001 for various models is:

For P = [(176000-105000)/105000]× 100%= 67.62%, rise.

For Q = [(88000-52500)/52500]× 100%= 67.62%, rise.

For R= [(70000-66000)/70000]× 100%= 5.71%, fall.

For S = [(44000-35000)/35000]× 100%= 25.71%, rise.

For T = [(52500-44000)/52500]× 100%= 16.19%, fall.

For U = [(35000-22000)/35000]× 100%= 37.14%, fall.

Therefore percentage rise/fall is minimum for model R.

Sol.3.(a). Required difference = 88000- 52500= 35500

(Using calculations in the Solution of Q. 1)

Sol.4.(b). If the percentage production of P type cars in 2001 = percentage production of P type cars in 2000 30%,

then, number of P type cars produced in 2001 = 30% of 440000= 132000.

Sol.5.(c). Number of S type cars which remained unsold in 2000 =15% of 35000 and number of S type cars which remained unsold in 2001 = 15% of 44000.

Therefore total number of S type cars which remained unsold

=15% of (35000+44000)=15% of 79000=11850.